Q - five years hence, the age of Jacob will be three time that of his son . five years ago Jacob's age was seven times that of his son . what are their present ages .
Answers
Answered by
2
Step-by-step explanation:
let x present age of jacob and y be the age of his son
x+5=3(y+5)
x _ 5 =7(y_5)
2x =3y+15+7y_35
2x=10y_20
x=5y_10
5y_5=3y+15
2y=20
y=10
x=5×10_10
x= 40
Answered by
1
Answer:
j=Jacob
s=son
—5 years ratio j : s = 7:1
Ratio difference 7–1 =6
+5 years ratio 3:1
Ratio difference 3–1 =2
Make ratio difference same so multiply +5 ratio with 3 then ratio will be 9:3
Difference between —5 and +5 years is 10 years
Absorb ratios 7:1. And 9:3 and there difference is also equal
Then 9–7 = 2
Or 3–1 = 2
Then this 2 equals to 10 years
i.e means 1 part is 5 years
Take any one of above equation
—5 years ratio is 7:1 multiply with 5
—5 years ages are Jacob 35 and son 5
Now there ages are 40 and 10
Similar questions