Q. For any positive integer n, prove that n3 – n is divisible by 6.
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Case 2: Consider n = 2q + 1
Since, n (n – 1) (n + 1) is divisible by 2 and 3.
Therefore, as per the divisibility rule of 6,
the given number is divisible by six.
n3 – n = n (n – 1) (n + 1) is divisible by 6.
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