Question

Q. For what values of k, the roots of the equation x^2+4x+k=0 are real?​

Answer 1

Answer:

${x}^{2} + 4x + k = 0 \\ if \: \: \bold{ k = 4 }\\ {x}^{2} + 4x + 4 = 0 \\ Then, \\The \: \: roots \: \: of \: \: the \: \: equation \: \: are \: \: real \\ \\ {x}^{2} + 4x + 4 = 0 \\ {x}^{2} + 2x + 2x + 4 = 0 \\ x(x + 2) + 2(x + 2) = 0 \\( x + 2)(x + 2) = 0 \\ x +2 = 0 \: \: \: or \: \: \: x + 2 = 0 \\ x = - 2 \: \: \: or \: \: \: x = - 2$