Question

Q. form linear equation with one variable...

a) if the current age of father is three times the age of his son, after twenty years the age of father will become two times the age of his son.​

Answer 1

Step-by-step explanation:

Let the present age of son =x

Then, the present age of father =3x

According to the question,

The age of son after 20 years =x+20

And the age of father after 20 years =2(x+20)

Therefore,

3x+20=2(x+20)

3x+12=2x+40

5x = 40-12

5x = 28

X= 5.6

So, the present age of son is 6 years approx and present age of father is 6×3 = 18 years approx .

Answer 2

Answer:

let the present age of son=y

then , the present age of father=3y

ACC to given question

the age of son after 20 years =y+20

the age of father after 20 years=2(y+20)

3y+20=2(y+20)

3y+12=2y+40

5y=40-12

5y=28

y=5.6

the age of son after 20 years is 6 years

the age of father after 20 years is 6×3 is 18 years