Q. From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semi-circular portion with BC as diameteris cut off. Find the area of remining paper (use π = 22/7)
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Answered by
4
Answer:
Length of paper, AB = l = 40cm
Width of paper, AD = b = 28cm
Area of paper = l × b = 40 × 28 = 1120 cm2
Diameter of semi-circle = 28cm
∴ Radius of semi-circle, r = 14cm
Thus, area of semi-circle = 1/2. πr2
= 1/2 × 22/7 × 14 × 14
= 308cm2
∴ Area of remaining paper = 1120 – 308 = 812 cm2
Answered by
0
Answer:
812 sq cm
Step-by-step explanation:
area of rect=40*28=1120sq cm
area of semi cir
=(22/7)*14*14*0.5=22*14
=308 sq cm
so remaning area
=1120-308
=812 sq cm
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