Question

Q. Froma right circular cylinder of radius 7 cm, height 24cm of conical cavity of same base radius and of same height hollowed out. find the volume and whole surface of remaining solid .

PLZ ans this question..​

Answer 1

Answer:

Answer:

Given,

height (h) of the conical part = height (h) of the cylinder part = 24 cm

radius (r) of the cylinder part = 7 cm

$\begin{gathered} slant \: \: height \: (l) \: of \: \: conical \: part = \sqrt{r {}^{2} + h {}^{2} } \\ \sqrt{(7) {}^{2} + (24) {}^{2} } = \sqrt{49 + 576 } \\ = \sqrt{625} = 25\end{gathered} </p><p>slantheight(l)ofconicalpart= </p><p>r </p><p>2</p><p> +h </p><p>2</p><p> </p><p> </p><p> </p><p>(7) </p><p>2</p><p> +(24) </p><p>2</p><p> </p><p> </p><p> = </p><p>49+576</p><p> </p><p> </p><p>= </p><p>625</p><p> </p><p> =25$

total surface area of the remaining solid will be

=CAS of cylindrical part + CAS of conical part + Area of cylindrical base

$2\pi \: rh + \pi \: rh + \pi \: r {}^{2}2πrh+πrh+πr </p><p>2$

2 × 22/7 × 7 × 24 + 22/7 × 7 × 25 + 22/7 × 7 × 7

44 × 24 + 22 × 25 × 22 × 7

=1056 + 550 + 157 = 1760 cm²

the total surface area of the remaining solid is 1760 cm²

Answer 2

Answer:

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