Question

Q. Given the cell Ag |AgCl(s) NaCl (0.05 M)||AgNO, (0.30) Ag a. Write half reaction occurring at the anode. b. Write half reaction occurring at the cathode. c. Write the net ionic equation of the reaction.​

Answer 1

(a). LHS electrode is anode and half reduction.

Ag++Cl−→AgCl(s)+e−

(b) RHS electrode is cathode and half reaction is reduction

Ag+e→Ag(s)

(c) from equation (i) and (ii) cell reaction is :

Cl−(0.05M)+Ag+(0.30M)→AgCl(S)

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Answer 2

(a). LHS electrode is anode and half reduction.

Ag++Cl−→AgCl(s)+e−

(b) RHS electrode is cathode and half reaction is reduction

Ag+e→Ag(s)

(c) from equation (i) and (ii) cell reaction is :

Cl−(0.05M)+Ag+(0.30M)→AgCl(S)

hope it helps you