Question

Q. i) An object of height 8 cm is placed at a distance of 25 cm in front of a lens having radius of curvature 30 cm The image of an object is obtained on the screen. Determine the nature of lens used. Also find the nature, size and position of image formed​

Answer 1

$\boxed{\bf{\blue{\longrightarrow Answer:}}}$

• h = 8cm
• u = -25cm
• f = 15cm
• Using lens formula
• $\frac{1}{v} = \frac{1}{f} + \frac{1}{u}$
• $\frac{1}{v} = \frac{1}{15} - \frac{1}{25}$
• $v = 37.5$
• $m = \frac{v}{u} = \frac{75}{2 \times - 25} = - 1.5$
• So image is Real and inverted and Is magnified
• Lens is Convex lens