Q. i) An object of height 8 cm is placed at a distance of 25 cm in front of a lens having radius of curvature 30 cm The image of an object is obtained on the screen. Determine the nature of lens used. Also find the nature, size and position of image formed.
Answers
Answered by
0
Answer:
The image is of 11.2 CM height and is formed at a distance of 37.5cm in front of the lens. The image formed is real and inverted.
Explanation:
Lens used is convex lens as the image is formed on the screen
Height of object(h)=8 cm
Object distance (u) = -25 cm
Radius of curvature (R) =30 cm
focal length (f) =R/2
=30/2
=15 cm
According to lens formula,
1/f=1/v-1/u
1/15=1/v-1/(-25)
1/15=1/v+1/25
1/15-1/25=1/v
(25-15)/375=1/v
10/375=1/v
v=37.5cm
According to magnification formula,
v/u=h'/h
37.5/(-25)=h'/8
-7.1*8/5=h'
-1.4*8=h'
h'= -11.2
HOPE THIS BRING A SMILE IN YOUR FACE
Similar questions