Q. If k is the ratio of the roots of the equation x² - ax + b=0, then the value of \frac{ {k}^{2} + 1}{k}
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Answer:
We know that equation ax
2
+bx+c=0
Then sum of roots =
a
−b
Let the roots of the equation be a and b.
Then, a + b = p
ab = q
b
a
=k
Now,
1+k
2
k
=
1+(
b
a
)
2
b
a
=
a
2
+b
2
ab
=
(a+b)
2
−2ab
ab
=
p
2
−2q
q
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