Question

Q. If n = (2 x 10^100) +3, then find the sum of the digits of n^2.

please tell me the answer
#answer needed with explanation
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Answer 1

Answer:

n=(2×10^100)+3

=(20^100)+3

=23^100

n^2=(23^100)^2

=23^200

therefore

n^2=23^200

I hope it helps you