Question

Q.
If the zeroes of the polynomial f(x) = x - 3x + x + 1 area-a-b, a,a+b then​

Answer 1

Answer:

Step-by-step explanation:

From the data,  $f(x) = x^{3} -3x^{2} +x+1$

And the zeroes of f(x) are : a-b,a,a+b.

sum of zeroes = a-b+a+a+b = 3a = -(-3)/1

                                         => a = 1.

product of the zeroes = (a-b)a(a+b) = $a(a^{2}-b^{2} )$ = 1/1

                                                         => 1 ( 1 - $b^{2}$) = 1

                                                         =>  $b^{2}$ = 0

                                                         =>  b =0

Therefore, the zeroes are 1,1,1.