Q . If the zeroes of the quadratic polynomial x² + (a + 1) x + b are 2 and -3, then what is the value of a and b ?
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Answer:
a = 0 , b = -6
Step-by-step explanation:
If α and β are the zeroes of quadratic equation then:
then α+β= -(a+1)
-(a+1) = 2+(-3) = -1 (given α=2 , β= -3)
-a-1=-1
a=0
αβ = b (given α=2 , β= -3)
b=(2)(-3)
b= -6
Equation will be x²+x-6=0
x²+3x-2x-6=0
x(x+3)-2(x+3)=0
(x-2)(x+3)=0
x=2 , x=-3
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