solve. (a-b)x + (a+b)y = a^2-2ab-b^2 ; (a+b)x + (a+b)y = a^2 + b^2
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Step-by-step explanation:
(a-b)x+(a+b)y = a²-2ab-b²...............(1)
(a+b)x+(a+b)y = a²+b²......................(2)
substracting (2) from (1)
-2bx = -2ab-2b²
=> bx = b(a-b)
=> x = (a-b)
substituting the value of x in (1)
(a+b)y +(a-b)² = a²-2ab-b²
=> (a+b)y = a²-2ab-b²-a²-b²+2ab
=> (a+b)y = -2b²
=> y = -2b²/(a+b)
therefore
x = (a-b)
y = -2b²/(a+b)
hope this helps you
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