(Q) If x^2/y^2+y^2=14
find the value of
of x^3/y^3+y^3/x^3.
please answer me in detail.
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Answer:
Answer 981+2+3=61+4+9=141+8+27=36So X=1Y=2 and Z=3And1+16+81=98 ans
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ANSWER
2x+3y=14,2x−3y=2
Adding :
2x+3y=14
2x−3y=2
__________
4x=16
x=4
∴xy=4×2
=8
2×4+3y=14
8+3y=14
3y=6
y=2
solution
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