Math, asked by akhila123487, 10 months ago

(Q) If x^2/y^2+y^2=14
find the value of
of x^3/y^3+y^3/x^3.
please answer me in detail.
OK guys.

Answers

Answered by dhruv220605
0

Answer:

Answer 981+2+3=61+4+9=141+8+27=36So X=1Y=2 and Z=3And1+16+81=98 ans

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Answered by drijjani50
1

ANSWER

2x+3y=14,2x−3y=2

Adding :

2x+3y=14

2x−3y=2

__________

4x=16

x=4

∴xy=4×2

=8

2×4+3y=14

8+3y=14

3y=6

y=2

solution

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