Question

Q in ABC angle A = 100 and AB=AC. find angle B and C.

Answer 1

as AB = BC therefore angle B = angle C 
So A + B + C = 180 degree
Therefore, angle B = angle C = 40 degree

Answer 2

Answer:

$\angle B = \angle C = 40\degree$

Step-by-step explanation:

$Given, \\In\: \triangle ABC\\ \angle A=100\degree,\\and\:AB=AC.$

$ABC \:is \:an\: isosceles\:triangle$

$AB=AC\: \implies \angle C=\angle B$

\* Angles opposite to equal sides are equal *\

$Now,\\\angle A+\angle B+\angle C=180\degree$

\* Angle sum property *\

$\implies 100\degree +\angle B + \angle B = 180$

$\implies 2\angle B = 180-100$

$\implies \angle B = \frac{80}{2}$

Therefore,.

$\angle B = \angle C = 40\degree$

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