Question

Q. In an experiment, student observed 5 observations of a length which
are :- 2.46cm, 2.48 cm, 2.50 cm, 2.52 cm, 2.54cm
Determine all four errors.​

Answer 1

Explanation:

2.46 +2.48+2.50+2.52+2.54. add all nos. which. is equal to12.50 . mean. absolute error =1/5((2.46-12.50)+(2.48-12.50)+(2.50-12.50)+(2.52-12.50 ) +(2.54-12.50))m. =-10.12divide by5. =-202.4.=relative. error=-202.4 divide by12.50.=-016192. %error=16.192