Question

Q) In Fig. 6.18, if LM || CB and LN || CD, prove that AM/AB=AN/AD
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Answer 1

Step-by-step explanation:

ther is no fig

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Answer 2

Proof:

In ∆ABC:

LM || CB

So,

$\frac{AM}{AB} = \frac{AL}{AC} \: — \: (1)$

Similarly,

In ∆ADC:

LN || CD

So,

$\frac{AN}{AD} = \frac{AL}{AC} \: — \: (2)$

Equating (1) & (2):

$\frac{AM}{AB} = \frac{AN}{AD}$

HENCE PROVED