Math, asked by amritha855, 2 months ago

Q) in quadrilateral ABCD, BM and DN are drawn perpendicular to AC such that BM=DN if BR = 8cm, then BD is

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Answered by agastya8422
3

Answer:

GivenABCD is a quadrilateral in which diagonals AC and BD intersect each other at P

Also,DN⊥AC and BM⊥AC

DN=BM

In △DNP and △BMP we have

∠DPN=∠BPM since they are vertically opposite angles.

∠DNP=∠BMP since each are equal to 90

DN=BM(given)

⇒△DNP≅△BMP by AAS postulate.

⇒DP=BP=8cms by CPCT

We have BD=BP+DP=8+8=16cms from the diagram.

Answered by sanganna84
0

Answer:

16 cm

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