Q is a point on the side SR of a Δ PSR such thatPQ = PR. Prove that PS PQ.
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given : PSR is a triangle.and PQ = PR
TPT : PS > PW
proof :
in Δ PQR, PQ = PR
therefore
∠PQR = ∠PRQ
now ∠prq >∠psq
∠PRQ> PSQ or ∠PRS > PSR
now in the triangle PSR : ∠PRS> ∠PSR
therefore PS >PR
thus PS > PQ
HENCE ITS PROVED
TPT : PS > PW
proof :
in Δ PQR, PQ = PR
therefore
∠PQR = ∠PRQ
now ∠prq >∠psq
∠PRQ> PSQ or ∠PRS > PSR
now in the triangle PSR : ∠PRS> ∠PSR
therefore PS >PR
thus PS > PQ
HENCE ITS PROVED
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