Q. No. 2, 3, 4, 5 plz
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Answered by
1
2.
K = hf - W
= 6.2eV - 4.2eV
= 2eV
= 2 * 1.602 * 10^-19
≈ 3 * 10^-19 J
__________________
3.
W = hc/λ
= 12400 eVÅ/λ
= 12400 eV Å/(5000 Å)
= 2.48 eV
= 2.48 * 1.602 * 10^-19
≈ 4 * 10^-19 J
K = hf - W
= 6.2eV - 4.2eV
= 2eV
= 2 * 1.602 * 10^-19
≈ 3 * 10^-19 J
__________________
3.
W = hc/λ
= 12400 eVÅ/λ
= 12400 eV Å/(5000 Å)
= 2.48 eV
= 2.48 * 1.602 * 10^-19
≈ 4 * 10^-19 J
JunaidMirza:
You're welcome :)
It's OK
4 th one plz
Can u try
I'll answer few hours later. Busy right now
OK
Answer it n tomorrow is my paper
Stopping potential = -(hf - W)/e = -(6eV - 2.1eV)/e = -3.9V
OK tnx
You're welcome :)
Answered by
1
5. Threshold frequency= 4x10^14
So the min energy= hν
= 6.626x4x10^-20
=2.64x10^-19J
So the min energy= hν
= 6.626x4x10^-20
=2.64x10^-19J
Thanku
Welcome
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