Question

q. no 4
plzzzzzxz give this answer....​

Answer 1

total no. of student in first year = 40,36,463 + 72,14, 587 = 1,12,51,050

total no. of student on second year = 1,12,51, 050 + 6,31,421 = 1,18,82,471

total no. of student in two years = 1,12,51,050 +1,18,82,471 = 2,31,33,521

Answer 2

Hey mate here we go

$now \: the \: total \: number \: of \: students \\ appeared \: in \: last \: year \: is \\ 4036463(p) + 7214587(f) = 11251050 \\ p = pass \: f = failed \\ \\ this \: year \: they \: told \: that \: students \: \\ were \: appeared \: more \: number \: then \: \\ last \: year \\ i.e \: 11251050(last) + (11251050 + 631421)this \\ = 23133521$

This much students were appeared in both years.

I hope this will helps you

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