Question

Q.No.7. Current of L A flows through an electric bulb for 4.8 second how
many electrons flow through bulb in given time?​

Answer 1

Answer:

$L*3*10^{19}$

Explanation:

we know I = q/t

and we also know charge is quantised

i.e. Q = ne

substituting that in the equation

I = L = Q/t

L = ne/t

  n = Lt/e

     = $\frac{L*4.8}{1.6*10^{-19} }$

     = $L*3*10^{19}$

thanks