q. no. 7 explain please tell
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Given : area of square is equal to 60025sq.m
speed of man while cycling is equal to 118km/hr
To find : time taken by the cyclist to return at the starting point
Solv : So as we know that area of square = a^2
then, √60025 = a
a = 245
now , perimeter of square = 4a
then 4a = 4x245
which is equal to 980
so total distance travelled by the cyclist in one round of the square field is 980 m.
speed of the cyclist can be written as 118000m/3600sec
so actual speed of the cyclist in sec =32.8m per sec
So as we know that time = D/T
we get = 980 /32.8 SEC
= 29.87 SEC which can be either written as 30 sec
speed of man while cycling is equal to 118km/hr
To find : time taken by the cyclist to return at the starting point
Solv : So as we know that area of square = a^2
then, √60025 = a
a = 245
now , perimeter of square = 4a
then 4a = 4x245
which is equal to 980
so total distance travelled by the cyclist in one round of the square field is 980 m.
speed of the cyclist can be written as 118000m/3600sec
so actual speed of the cyclist in sec =32.8m per sec
So as we know that time = D/T
we get = 980 /32.8 SEC
= 29.87 SEC which can be either written as 30 sec
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