Question

Q. No.8. AB and CD are respectively the smallest and longest sides of quadrilateral
ABCD. Show that angle A > angle C and angle B > angle D​

Answer 1

Answer:

Show that ∠A > ∠C and ∠B > ∠D. Given: AB is the smallest side CD is the longest side To prove: ∠A > ∠C & ∠B > ∠D Proof: Join A & C, and mark the angles In ∆ ABC,

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