Q no. 8 and 9 plzz solve
Attachments:
Answers
Answered by
3
8. √3² + √3m + √6 = 0
3 + √3m + √6 = 0
(-√6 - 3 )/ √3 = m
9. Let a = length , b = breadth
ab= 6000 (eq 1)
=> (a+20)= 2b
a = 2b - 20
Putting value of a in eq 1
= 2b² - 20b = 6000
b² - 10b = 3000
= b² - 10b - 3000 = 0
b = -50, 60
b = 60 m
Putting value of b in eq 1
a x 60 = 6000
a = 100 m
Therefore length of the garden = 100 m
3 + √3m + √6 = 0
(-√6 - 3 )/ √3 = m
9. Let a = length , b = breadth
ab= 6000 (eq 1)
=> (a+20)= 2b
a = 2b - 20
Putting value of a in eq 1
= 2b² - 20b = 6000
b² - 10b = 3000
= b² - 10b - 3000 = 0
b = -50, 60
b = 60 m
Putting value of b in eq 1
a x 60 = 6000
a = 100 m
Therefore length of the garden = 100 m
rajc7:
yer option nhi hai
Similar questions
Computer Science,
7 months ago
English,
7 months ago
Math,
1 year ago
Biology,
1 year ago
English,
1 year ago