Q no. 9 please answer me
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In triangle ABC
angle A+B+C=180 deg
so, A/2 + B/2 + C/2=90 ----- eq1
and in triangle BOC
angle B/2+C/2+(BOC)=180
and angle B/2+C/2=90-A/2
So, angle BOC=180-(90-A/2)
BOC=90+A/2
PLZ MARK IT AS BRAINLIEST
angle A+B+C=180 deg
so, A/2 + B/2 + C/2=90 ----- eq1
and in triangle BOC
angle B/2+C/2+(BOC)=180
and angle B/2+C/2=90-A/2
So, angle BOC=180-(90-A/2)
BOC=90+A/2
PLZ MARK IT AS BRAINLIEST
RaunakRaj:
thank you
Answered by
1
hope this will help you
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