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We have to first find the initial and final millimoles. of acetic acid.
Initial millimoles of acetic acid = 0.06*50 = 3
Final millimoles of acetic acid = 0.042*50 = 2.1
Now,
Acetic acid that is absorbed = 3 - 2.1 = 0.9 moles
Weight of acetic acid that will get absorbed after 1 hour= 0.9*60/ 10^3.= 54mg
Amount of acetic acid absorbed per mg of charcoal = 54/3 = 18mg
So correct option is 4
Initial millimoles of acetic acid = 0.06*50 = 3
Final millimoles of acetic acid = 0.042*50 = 2.1
Now,
Acetic acid that is absorbed = 3 - 2.1 = 0.9 moles
Weight of acetic acid that will get absorbed after 1 hour= 0.9*60/ 10^3.= 54mg
Amount of acetic acid absorbed per mg of charcoal = 54/3 = 18mg
So correct option is 4
Anonymous:
sure:)
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