Question

Q . Prove that sinΘ ÷ cosΘ = tanΘ.

Answer 1

$\sin \: theta = \frac{p}{h} \\ here \: p \: is \: perpendicular \\ h \: is \: height \\ cos \: theta = \frac{b}{h} \\ here \: b \: is \: base \\tan \: theta \: = \frac{p}{b} \\ to \: prove \\ \frac{sin \: theta}{cos \: theta } = tan \: theta \\ lhs \\ \frac{ \frac{p}{h} }{ \frac{b}{h} } \\ \frac{p \times h}{b \times h} \\ \frac{p}{b} \\ rhs \\ tan \: theta \: \\ \frac{p}{b \: } \\ lhs = rhs \\ hence \: proved. \\ hope \: it \: helps \: u$

Answer 2

sin theta = opposites / hypotenuse


cos theta = adjacent /hypotenuse


sin theta / cos theta = opposite / adjacent

tan theta = opposite / adjacent

thus sin theta ÷ cos theta = tan theta


this is your answer........


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