Question

Q:-solve and verify the equation
$\frac{1}{2} - \frac{1}{3} (x - 1) + 2 = 0$​

Answer 1

$\green{\bold{\underline{ ✪ UPSC-ASPIRANT✪ }}}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Q:-solve and verify the equation

$\frac{1}{2} - \frac{1}{3} (x - 1) + 2 = 0$

$\huge\tt\underline\blue{Answer }$

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$⟹ \frac{1}{2} - \frac{1}{3} (x - 1) + 2 = 0</p><p>$

$⟹</p><p> \frac{3 - 2(x - 1) + 2}{6} = 0$

$⟹</p><p> \frac{1}{6} (x - 1) + 2 = 0$

$⟹</p><p>(x - 1) + 2 = 0$

$⟹</p><p>x - 1 = - 2$

$⟹</p><p>x = - 2 + 1$

$⟹</p><p>x = - 1$

CHECK:-

$⟹ \frac{1}{2} - \frac{1}{3} ( - 1 - 1) + 2</p><p>$

$⟹</p><p> \frac{3 - 2( - 2) + 2}{6} = 0$

$⟹</p><p> \frac{1}{6} ( - 2) + 2 = 0$

$⟹</p><p> \frac{0}{6} = 0$

$⟹</p><p>0 = 0$

THEREFORE,L.H.S=R.H.S

VERIFIED ✓

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HOPE IT HELPS YOU..

_____________________

Thankyou:)

Answer 2

Answer:

$\pink{\bold{\underline{ ✪Silentkiller Here !! ✪ }}}</p><p></p><p>$

$\gray{\bold{\underline{\underline{QUESTION:-}}}} </p><p>$

Q:-Solve and verify the equation

$\frac{1}{2} - \frac{1}{3} (x - 1) + 2 = 0$

$\huge\tt\underline\blue{Answer } </p><p>$

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _✍️

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$⟹ \frac{1}{2} - \frac{1}{3} (x - 1) + 2 = 0$

$⟹ \frac{3 - 2(x - 1) + 2}{6}$

$⟹ \frac{1}{6} (x - 1) + 2 = 0$

$⟹ (x - 1) + 2 = 0⟹(x−1)+2=0$

$⟹ x - 1 = - 2⟹x−1=−2</p><p>$

$⟹ x = - 2 + 1⟹x=−2+1$

$⟹ x = - 1⟹x=−1$

CHECK:-

$⟹ \frac{1}{2} - \frac{1}{3} ( - 1 - 1) + 2$

$⟹ \frac{3 - 2( - 2) + 2}{6} = 0$

$⟹ \frac{1}{6} ( - 2) + 2 = 0$

$⟹ \frac{0}{6} = 0$

THEREFORE,L.H.S=R.H.S

$\tt \red{Hence \: VERIFIED ✓</p><p>}$

══════════XXX═════════════

HOPE IT HELPS YOU..

_____________________

Thankyou:)