Question

Q:-solve and verify the equation
$\frac{1}{2} - \frac{1}{3} (x - 1) + 2 = 0$
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Answer 1

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⟹ \frac{1}{2} - \frac{1}{3} (x - 1) + 2 = 0⟹

2

1

−

3

1

(x−1)+2=0

⟹ \frac{3 - 2(x - 1) + 2}{6} = 0⟹

6

3−2(x−1)+2

=0

⟹ \frac{1}{6} (x - 1) + 2 = 0⟹

6

1

(x−1)+2=0

⟹ (x - 1) + 2 = 0⟹(x−1)+2=0

⟹ x - 1 = - 2⟹x−1=−2

⟹ x = - 2 + 1⟹x=−2+1

⟹ x = - 1⟹x=−1

CHECK:-

⟹ \frac{1}{2} - \frac{1}{3} ( - 1 - 1) + 2⟹

2

1

−

3

1

(−1−1)+2

⟹ \frac{3 - 2( - 2) + 2}{6} = 0⟹

6

3−2(−2)+2

=0

⟹ \frac{1}{6} ( - 2) + 2 = 0⟹

6

1

(−2)+2=0

⟹ \frac{0}{6} = 0⟹

6

0

=0

⟹ 0 = 0⟹0=0

THEREFORE,L.H.S=R.H.S

VERIFIED ✔️