Math, asked by ruhi6488, 6 hours ago

Q

Solve graphically the system of linear equation

4X-3y + 4 = 0 and 4x - 3y -20 = 0
Find the area bounded by these line and
x-axis​

Answers

Answered by amansharma264
69

EXPLANATION.

System of linear equation graphically.

⇒ 4x - 3y + 4 = 0. - - - - - (1).

⇒ 4x - 3y - 20 = 0. - - - - - (2).

As we know that,

From equation (1), we get.

⇒ 4x - 3y + 4 = 0. - - - - - (1).

Put the value of x = 0 in the equation, we get.

⇒ 4(x) - 3y + 4 = 0.

⇒ - 3y + 4 = 0.

⇒ - 3y = - 4.

⇒ 3y = 4.

⇒ y = 4/3.

⇒ y = 1.33.

Their Co-ordinates = (0,1.33).

Put the value of y = 0 in the equation, we get.

⇒ 4x - 3(0) + 4 = 0.

⇒ 4x + 4 = 0.

⇒ 4x = - 4.

⇒ x = - 1.

Their Co-ordinates = (-1,0).

From equation (2), we get.

⇒ 4x - 3y - 20 = 0. - - - - - (2).

Put the value of x = 0 in the equation, we get.

⇒ 4(0) - 3y - 20 = 0.

⇒ - 3y - 20 = 0.

⇒ - 3y = 20.

⇒ y = - 20/3.

⇒ y = - 6.66.

Their Co-ordinates = (0,-6.66).

Put the value of y = 0 in the equation, we get.

⇒ 4x - 3(0) - 20 = 0.

⇒ 4x - 20 = 0.

⇒ 4x = 20.

⇒ x = 5.

Their Co-ordinates = (5,0).

Both lines parallel to each other and never intersects each other.

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Saby123: Nice!!!
amansharma264: Thanku so much
Answered by Rudranil420
72

Answer:

Question :-

  • Solve graphically the system of linear equation 4x - 3y + 4 = 0 and 4x - 3y -20 = 0. Find the area bounded by these line and x-axis.

Given :-

  • 4x - 3y + 4 = 0 and 4x - 3y -20 = 0.

Find Out :-

  • Find the area bounded by these line and x-axis.

Solution :-

Equation are :

➙ 4x - 3y + 4 = 0 __________ (1)

➙ 4x - 3y - 20 = 0 _________ (2)

From the equation (1), we get :-

➙ 4x - 3y + 4 = 0

Put x = 0 in the equation, we get :

➙ 4(x) - 3y + 4 = 0

➙ 4(0) - 3y + 4 = 0

➙ - 3y + 4 = 0

\cancel{-} 3y = \cancel{-} 4

➙ 3y = 4

{\small{\bold{\purple{\underline{y =\: \dfrac{4}{3}}}}}}

Their Co-ordinates = (0,4/3).

Again,

➙ 4x - 3y + 4 = 0

Put y = 0 in the equation, we get :

➙ 4x - 3(0) + 4 = 0

➙ 4x + 4 = 0

➙ 4x = - 4

➙ x = \sf \dfrac{- 4}{4}

{\small{\bold{\purple{\underline{x =\: - 1}}}}}

Their Co-ordinates = (-1,0).

Again,

From equation (2), we get :

➙ 4x - 3y - 20 = 0 _________ (2)

Put x = 0 in the equation, we get :

➙ 4(0) - 3y - 20 = 0

➙ - 3y - 20 = 0

➙ - 3y = 20

➙ y = \sf \dfrac{- 20}{3}

{\small{\bold{\purple{\underline{y =\: \dfrac{- 20}{3}}}}}}

Their Co-ordinates = (0, - 20/3).

Again,

➙ 4x - 3y - 20 = 0 _________ (2)

Put y = 0 in the equation, we get :

➙ 4x - 3(0) - 20 = 0

➙ 4x - 20 = 0

➙ 4x = 20

➙ x = \sf \dfrac{20}{4}

{\small{\bold{\purple{\underline{x =\: 5}}}}}

Their Co-ordinates = (5,0).


Saby123: Nice!!!
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