Q.subtract second expression from first
1) 5x²+4y²-6y+8;x²-5y²+2xy+3y-10
with step by step
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Here is ur answer mate:-
as we have to subtract (x²-5y²+2xy+3y-10) from (5x²+4y²-6y+8) we would do the following steps:-
(5x²+4y²-6y+8) - (x²-5y²+2xy+3y-10)
- first, we have to open up the brackets, i.e
5x²+4y²-6y+8-x²+5y²-2xy-3y+10
- Now, we have to arrange the like terms together from both the numbers to be subtracted, i.e
5x²-x² +4y²+5y² -6y-3y -2xy +8+10
- Now, it's easy for u to sum up all this, i.e u just have to do the basic operations between the like term
4x²+9y²-9y-2xy+18
- Now, no more calculation can be done in the above term as there is no more like terms.
- So, we got our result.
- Therefore by subtracting x²-5y²+2xy+3y-10 from 5x²+4y²-6y+8 we get 4x²+9y²-9y-2xy+18
I tried to explain u as easy as I can..
I suggest u to read the answer and do it practically on ur notebook, u will surely understand this
hope my answer is correct...
pls mark as brainliest and say thanks if it helps
may ur day be good ahead!!
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