Math, asked by janhavirathod50, 9 months ago

Q.subtract second expression from first


1) 5x²+4y²-6y+8;x²-5y²+2xy+3y-10

with step by step

Answers

Answered by Anonymous
4

Here is ur answer mate:-

as we have to subtract (x²-5y²+2xy+3y-10) from (5x²+4y²-6y+8) we would do the following steps:-

(5x²+4y²-6y+8) - (x²-5y²+2xy+3y-10)

  • first, we have to open up the brackets, i.e

5x²+4y²-6y+8-x²+5y²-2xy-3y+10

  • Now, we have to arrange the like terms together from both the numbers to be subtracted, i.e

5x²-x² +4y²+5y² -6y-3y -2xy +8+10

  • Now, it's easy for u to sum up all this, i.e u just have to do the basic operations between the like term

4x²+9y²-9y-2xy+18

  • Now, no more calculation can be done in the above term as there is no more like terms.

  • So, we got our result.

  • Therefore by subtracting x²-5y²+2xy+3y-10 from 5x²+4y²-6y+8 we get 4x²+9y²-9y-2xy+18

I tried to explain u as easy as I can..

I suggest u to read the answer and do it practically on ur notebook, u will surely understand this

hope my answer is correct...

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may ur day be good ahead!!

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