Physics, asked by yashvardhanmohit27, 9 months ago

[ Q. suppose there are three displacements of an object of magnitude (1) 5m,4m,7m.....(2)1m,5m,6m.......(3)2m,6m,9m....(4)1m,2m,5m.
in which of the following combinations resultant displacement of an object can be 0
Pls I need the answer​

Answers

Answered by nirman95
7

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First let's define what is Displacement !

Displacement is the shortest length between starting and stopping point of a journey.

Now net displacement can be zero only when starting and stopping point in a journey are same.

Since the Question provides us with 3 Displacement magnitudes , we can say that

  • Any combination which can form a triangle shall give same starting and stopping point and hence zero net displacement.

Rule for triangle construction is :

  • Sum of 2 sides > 3rd side.

Following this rule , we can say that only 1 option matches :

5m , 4m , 7m , because :

  • 5 + 4 > 7
  • 4 + 7 > 5
  • 5 + 7 > 4

So triangle construction is possible , hence net displacement will be zero only with this combination of vectors.

Answered by BlackPearl01
9

Answer:

First let's define what is Displacement !

Displacement is the shortest length between starting and stopping point of a journey.

Now net displacement can be zero only when starting and stopping point in a journey are same.

Since the Question provides us with 3 Displacement magnitudes , we can say that

Any combination which can form a triangle shall give same starting and stopping point and hence zero net displacement.

Rule for triangle construction is :

Sum of 2 sides > 3rd side.

Following this rule , we can say that only 1 option matches :

5m , 4m , 7m , because :

5 + 4 > 7

4 + 7 > 5

5 + 7 > 4

So triangle construction is possible , hence net displacement will be zero only with this combination of vectors.

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