Q. The 10th term of an Arithmetic Progression is 44 and its 15th term is 64. Find the A.P and its 21"
term.
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Answered by
30
Answer:
8, 12, 16...
88
Step-by-step explanation:
Let the first term and common difference be 'a' and 'd'.
10th term = 44 → a + 9d = 44
=> a = 44 - 9d
15th term = 64 → a + 14d = 64
=> (44 - 9d) + 14d = 64
=> 14d - 9d = 64 - 44
=> 5d = 20
=> d = 4
Thus, a = 44 - 9(4) = 8
Therefore AP is 8, 8 +4, 8 +2(4), 8 +3(4)...
AP is 8, 12, 16...
21st term = a + 20d = 8 + 20(4) = 88
Answered by
16
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