Math, asked by Gunjanstar, 3 months ago

Q. The 10th term of an Arithmetic Progression is 44 and its 15th term is 64. Find the A.P and its 21"
term.​

Answers

Answered by abhi569
30

Answer:

8, 12, 16...

88

Step-by-step explanation:

Let the first term and common difference be 'a' and 'd'.

10th term = 44 → a + 9d = 44

=> a = 44 - 9d

15th term = 64 → a + 14d = 64

=> (44 - 9d) + 14d = 64

=> 14d - 9d = 64 - 44

=> 5d = 20

=> d = 4

Thus, a = 44 - 9(4) = 8

Therefore AP is 8, 8 +4, 8 +2(4), 8 +3(4)...

AP is 8, 12, 16...

21st term = a + 20d = 8 + 20(4) = 88

Answered by Agamhargun
16

Hey, Here is your answer..

hope it will help you

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