Q. The frequency of a recessive allele in a large randomly mating population is 0.2. What is the frequency of: (a) The dominant allele? (b) The heterozygote?
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According to the given details in the question, the frequency of the recessive allele in a random mating population = 0.2.
(a) Since the whole population is considered = 1, the dominant allele should be present in the population in a number that leaves the recessive allele out.
So, dominant alleles + recessive alleles = 1
Dominant alleles + 0.2 = 1
Dominant alleles = 1 - 0.2 = 0.8
Thus, Dominant alleles = 0.8.
(b). The frequency of heterozygosity - There is a minimum of 2 heterozygous alleles in a mating population.
So, Heterozygosity = 2 x 0.8 x 0.2 = 0.32.
Thus, the frequency of the heterozygous carriers will be = 0.32.
(a) Since the whole population is considered = 1, the dominant allele should be present in the population in a number that leaves the recessive allele out.
So, dominant alleles + recessive alleles = 1
Dominant alleles + 0.2 = 1
Dominant alleles = 1 - 0.2 = 0.8
Thus, Dominant alleles = 0.8.
(b). The frequency of heterozygosity - There is a minimum of 2 heterozygous alleles in a mating population.
So, Heterozygosity = 2 x 0.8 x 0.2 = 0.32.
Thus, the frequency of the heterozygous carriers will be = 0.32.
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