Question

Q::The length of a playground is 16 m and breadth is 9 m .Find the area of the playground.

PLS ANSWER THIS QUESTION FAST......​

Answer 1

• Area of playground is 144 m².

Step-by-step explanation:

Given:-

• Length of playground is 16 m.
• Breadth of playground is 9 m.

To find:-

• Area of playground.

Solution:-

• We know if length and Breadth is given. Then shape of object is rectangle.

We know that,

Area of rectangle = l × b

In which,

• l is length of rectangle.
• b is breadth of rectangle.

l = 16 m

b = 9 m

Put length and Breadth in formula :

➝ 16 × 9

➝ 144

Therefore,

Area of playground is 144 m².

Answer 2

${\large{\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{blue}{\bf{\color{yellow}{⫷Question⫸}}}}}}$

The length of a playground is $16$ m and breadth is $9$ m .Find the area of the playground.

${\large{\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{blue}{\bf{\color{yellow}{⫷Given⫸}}}}}}$

• Length = $16$ m

• Breadth = $9$ m

${\large{\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{blue}{\bf{\color{yellow}{⫷To\:find⫸}}}}}}$

The area of the playground.

${\large{\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{blue}{\bf{\color{yellow}{⫷Solution⫸}}}}}}$

Length = $16$ m

Breadth = $9$ m

We know that:

$\blue{\boxed{\pink{Area=(Length×Breadth)\:unit²}}}$

Here,

• Length = $16$ m

• Breadth = $9$ m

So using the formula of area, we can easily find the area of the playground.

Area⇒

➳ $(16 × 9)$ m²

➳ $144$ m² $\bold\red{✯}$

${\large{\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{blue}{\bf{\color{yellow}{⫷Hence⫸}}}}}}$

Area = $144$ m²

${\large{\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{blue}{\bf{\color{yellow}{⫷Therefore⫸}}}}}}$

The area of the playground is $144$ m².

${\large{\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{blue}{\bf{\color{yellow}{⫷Done⫸}}}}}}$

----------------------------------------------

${\large{\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{blue}{\bf{\color{yellow}{⫷Know\:more⫸}}}}}}$

Area of square:-

$\large\green{\boxed{\orange{S×S = S²}}}$

$Where,\:“S”\:is\:the\:side.$

Area of rectangle:-

$\large\green{\boxed{\orange{L×B = LB}}}$

${Where,\:“L”\:is\:the\:length\:and}\\{“B”\:is\:the\: breadth.}$

Area of parallelogram:-

$\large\green{\boxed{\orange{B×H = BH}}}$

${Where,\:“B”\:is\:the\:base\:and}\\{“H”\:is\:the\: height.}$

Area of triangle:-

$\large\green{\boxed{\orange{{\frac{1}{2}}×B×H = {\frac{1}{2}}BH}}}$

${Where,\:“B”\:is\:the\:base\:and}\\{“H”\:is\:the\: height.}$

$\bold\green{\boxed{{\blue{✿}}{\pink{H}}{\blue{O}}{\green{P}}{\red{E}}{\purple{  }}{\orange{T}}{\pink{H}}{\blue{I}}{\green{S}}{\red{  }}{\purple{H}}{\orange{E}}{\pink{L}}{\blue{P}}{\green{S}}{\red{  }}{\purple{Y}}{\orange{O}}{\pink{U}}{\blue{✿}}}}$

$\bold\red{\boxed{{\blue{✿}}{\pink{H}}{\blue{A}}{\green{V}}{\red{E}}{\purple{  }}{\orange{A}}{\pink{  }}{\blue{N}}{\green{I}}{\red{C}}{\purple{E}}{\purple{  }}{\orange{D}}{\pink{A}}{\green{Y}}{\blue{✿}}}}$