Q. The pendulum of a certain clock has time period of 2.04sec . How fast or slow does the clock run during 24 hours ?
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Answered by
29
The pendulum of the clock has time period 2.04sec.
Now, No. or oscillation in 1 day = (24 × 3600)/2 = 43200
But, in each oscillation it is slower by (2.04 – 2.00) = 0.04sec.
So, in one day it is slower by,
= 43200 × (0.04) = 12 sec = 28.8 min
So, the clock runs 28.8 minutes slower in one day.
Now, No. or oscillation in 1 day = (24 × 3600)/2 = 43200
But, in each oscillation it is slower by (2.04 – 2.00) = 0.04sec.
So, in one day it is slower by,
= 43200 × (0.04) = 12 sec = 28.8 min
So, the clock runs 28.8 minutes slower in one day.
taeyeon:
But why did u divide it by 2 in no. of oscillations
Pls...tell me that one is the thing which I am not able to understand
Ohh....come on pls explain it to me
Answered by
4
2.04×24 fast does the clock run
How come u can solve it easily ....pls explain this that how did u get it
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