Q. The radii of two circles are 8 cm and 6 cm respectively. Find the radius of the circle having area equal to the sum of the areas of the two circles.
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Step-by-step explanation:
consider two circles of radii R1 and R2 respectively {where R1=8cm and R2=6cm}
let R3 be the radius of third circle.
Area of first circle+Area of second circle=Area of third circle
=π×R1 square + π×R2 square=π×R3 square
=22/7×8 square+22/7×6 square=22/7 ×R3 square
=1408/7+792/7=22/7×R3 square
=201.14+113.14=22/7×R3 square
=314.2=3.142×R3 square
=R3 square×3.142=314.2
=R3 square=314.2/3.142
=R3 square=100CM
=R3=10cm
Hence, radius of third circle R3=10cm.
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