Question

q
The relation between time t and distance x is t = ax + bx, where a and b are constants. The
acceleration is:
(AIEEE 2005, 4.300)
(2) 2by2
(3) -2av
(4) 2av
​

Answer 1

Answer:

0

Explanation:

Taking derivative

t=ax+bx

t=x(a+b)

x=t/(a+b)

dx/dt=1/a+b× d/dt of t

= 1/a+b×1

hence v(velocity)=1/a+b

dv/dt=d/dt 1/a+b

=0. (d/dt of constant is always 0)

Answer 2

Answer:

Explanation:

3