Question

Q.
The roots of x2-4x-12=0 are​

Answer 1

Answer:

x^2-4x-12=0

x^2-6x+2x-12=0

x(x-6) + 2(x-6)=0

(x-6)(x+2)=0

x=6 or x=-2

Answer 2

Answer:

by using middle split term

x²-4x-12 = 0

x² -( 6x - 2x)-12 = 0

x² -6x+2x -12 = 0

x (x-6) +2 (x-6) = 0

(x+2)(x-6) = 0

x+2

x = -2

x-6

x= 6

hence roots are -2 and 6