Math, asked by musalutampr2ab, 1 year ago

Q:The sum of a two- digit number and number formed by reversing the order of digits is 154.If the two digits differ by 4, find the number.

Answers

Answered by sonali91
96
Let one's plsce digit be x Let ten's place digit be 10y Let the no. Be x+10y On reversing no. Will be 10x+y A/Q x+10y+10x+y=154(1) Also x-y=4 →(2) In (1) equation X+10y+10x+y=154 11x+11y=154 so x+y=14→(3) Now putting x=y+4 ( from 2eq) in eq3 Y+4+y=14→2y=10 y=5, x=y+4=9 So the no. Is 59 or 95
Answered by ayushmanb14
17

Answer:your answer is in the attachment

Step-by-step explanation:take number as 10x + y

Attachments:
Similar questions