Q: The sum of three consecutive multiples of 3 is 72. What is the second largest number ? A) 27 B) 24 C) 21 D) 42
Answers
Answered by
7
Your solution :_----
Explanation:--
Let the numbers be 3x, 3x + 3 and 3x + 6.
Then,
=> 3x + (3x + 3) + (3x + 6) = 72
=> 9x + 9 = 72
=> 9x = 72-9
=> 9x = 63
=> x = 7
Largest number = 3x + 6 = 27.
=> Second largest number = 27 - 3 = 24
Hence,
Answer:--
B) 24
Hope it helps you
Explanation:--
Let the numbers be 3x, 3x + 3 and 3x + 6.
Then,
=> 3x + (3x + 3) + (3x + 6) = 72
=> 9x + 9 = 72
=> 9x = 72-9
=> 9x = 63
=> x = 7
Largest number = 3x + 6 = 27.
=> Second largest number = 27 - 3 = 24
Hence,
Answer:--
B) 24
Hope it helps you
Answered by
4
hey mate!!
let the three consecutive nos. be 3x,3x+3 and 3x+6
now, according to the question
3x+3x+3+3x+6=72
9x+9=72
9x=72-9
9x=63
x=63/9
x=7
now, first no. =3x = 3*7=21
second no. =3x+3=21+3=24
third no. =3x+6=21+6=27
second largest no. is 24
hope it helps!!
let the three consecutive nos. be 3x,3x+3 and 3x+6
now, according to the question
3x+3x+3+3x+6=72
9x+9=72
9x=72-9
9x=63
x=63/9
x=7
now, first no. =3x = 3*7=21
second no. =3x+3=21+3=24
third no. =3x+6=21+6=27
second largest no. is 24
hope it helps!!
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