Question

Q..The value of k such that (k - 2) x + (k+3) y-5=0 is parallel to the line 2x - y + 7 = 0​

Answer 1

Answer:

Given line equation,

(k−2)x+(k+3)y−5=0...(1)

(k+3)y=−(k−2)x+5

y=(k+32−k)x+k+35

Slope of this line =m1=(k+2)(2−k)

Line (1) is parallel to 2x−y+7=0

So, m1=m2

(k+3)(2−k)=2

2−k=2k+6

3k=−4

k=−4/3

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