Q.Two cross roads ,each of width 5m, run at right angles through the center of a rectangular park of length 60 m and breadth 40 m and parallel to its sides. Find the area of the roads. Also find cost of construction of the roads at the rate of rs 90per sq m.
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width =5 m
width =5 mlength of first parallel road 70 m
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.m
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area
area
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25
width =5 mlength of first parallel road 70 marea of first road 70×5=350 sq.mlength of second road 45 m area of second road =45×5=225 sq.marea of the common part of cross road with 5 m width that lies at the center of the park 5×5 = 225 sq.m area of roads = area of first road +area of second cross road−common area =(350+225)−25=575−25=550sqm cost of the construction per sq.m =Rs.105total cost =550×105=Rs 57750
- hope it helps you zara.
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