Question

Q.
Two numbers are in the ratio 3:4. If 4 is added to
each of the numbers, the ratio becomes 4:5. Find
the product of numbers.

Answer 1

Answer:

let x to be included in the ratio

3+x 4

___=------

4+x . 5

5(3+x)=4(4+x)

15 + 5x=16 +4x

x=1

if one is added to( 3:4)

then ratio become (4:5)

3×1=3

4×1=4

if 7 is added to each term

hope it helps u

Answer 2

• Let one number be 3M and another be 4M.

» If 4 is added to each of the numbers, the ratio becomes 4:5.

A.T.Q.

→ $\dfrac{3M\:+\:4}{4M\:+\:4}\:=\:\dfrac{4}{5}$

Cross-multiply them

→ 5(3M + 4) = 4(4M + 4)

→ 15M + 20 = 16M + 16

→ 15M - 16M = 16 - 20

→ - M = - 4

→ M = 4

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• One number = 3(M) = 3(4) = 20

• Another number = 4(M) = 4(4) = 16

__________ [ ANSWER ]

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✡ VERIFICATION :

From above calculations we get M = 4

Put value of M in this : 5(3M + 4) = 4(4M + 4)

=> 15M + 20 = 16M + 16

=> 15(4) + 20 = 16(4) + 16

=> 60 + 20 = 64 + 16

=> 80 = 80

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