Q=Two trees,A and B are on the same side of a river .From a point C in the river the distance of the trees A and B is 250 m and 300 m,respectively .If the angle C is 45o ,find the distance b/w the trees (use root 2 =1.44).
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131
in ΔABC
∠C = 45
AC = 250 m
BC = 300m
by applying the cosine rule
a²= b² + c² - 2bc cos A
so,
AB² = AC² + BC² - 2 AC BC cos C
= 250² + 300² - 2 x 250 x 300 x cos 45
AB²= 46433.98
taking under root
AB = 215.5 m
∠C = 45
AC = 250 m
BC = 300m
by applying the cosine rule
a²= b² + c² - 2bc cos A
so,
AB² = AC² + BC² - 2 AC BC cos C
= 250² + 300² - 2 x 250 x 300 x cos 45
AB²= 46433.98
taking under root
AB = 215.5 m
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12
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