Q) What is the difference between the sum of first 20 terms and the next 20 terms of the arithmetic sequence 6,10,14.....
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Answer:
In the first case
A.P=6,10,14
d=10-6=4
n=20
a=6
S=n/2[2a+(n-1)d]
S=20/2[2*6+(20-1)4]
S =10[11+(19*4)]
S=10[11+76]
S=10*87
S= 870
In the second case
a =6
d=4
n=40
S=40/2{2*6+[40-1]4}
S = 20{11+[39*4]}
S=20{11+156}
S = 20*167
S = 3340
Difference = 3340/870=3.84
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