Question

Q.What is the point of intersection of medians of a triangle whose vertices are (-1,0), (5,-2) and (8,2).

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Answer 1

Mid point of triangle=[x1+x2+x3÷3 , y1+y2+y3÷3] [(-1)+5+8÷3 , 0-2+2÷3] =》[12/3 , 0/3] =》[4,0]

Answer 2

The point of intersection of medians of a triangle is the centroid of the triangle.
It is given by (x,y) where

$x= \frac{x_1+x_2+x_3}{3};\ y=\frac{y_1+y_2+y_3}{3}$

$x= \frac{-1+5+8}{3};\ y= \frac{0-2+2}{3}\\ \\x= \frac{12}{3};\ y= \frac{0}{3}\\ \\x=4;\ y=0\\ \\The\ required\ point\ is\ \boxed{(4,0)}$