Question

Q. ​What the current through an ideal p-n junction diode shown in figure below :


zero

10 mA

20 mA

50 mA

Answer 1

Answer:

C. 20 mA

Explanation:

Positive terminal of both batteries are connected to ground. Hence it is same point.

Potential Difference across diode and register = -1 - (-3) = 2 V

Now diode is in forward bias.

So current I = 2/ 100

therefore, I = 2 mA

Hence answer is C. 2 mA